Question

Two corners of an isosceles triangle are at `(4 ,8 )` and `(5 ,3 )`. If the triangle's area is `5`, what are the lengths of the triangle's sides?

Answer 1

Measure of the three angles are (2.55, 3.2167, 3.2167)

Explanation:

Length `a = sqrt((5-4)^2 + (3-8)^2) = sqrt 26 = 5.099`

Area of `Delta = 5`
`:. h = (Area) / (a/2) = 5 / (5.099/2) = 5 / 2.55 = 1.9608`
`side b = sqrt((a/2)^2 + h^2) = sqrt((2.55)^2 + (1.9608)^2)`
`b = 3.2167`

Since the triangle is isosceles, third side is also `= b = 3.2167`

Measure of the three sides are (2.55, 3.2167, 3.2167)