Two corners of an isosceles triangle are at (1 ,2 )(1,2) and (3 ,1 )(3,1). If the triangle's area is 12 12, what are the lengths of the triangle's sides?

1 Answer
Dec 11, 2017

Measure of the three sides are (2.2361, 10.7906, 10.7906)

Explanation:

enter image source here
Length a = sqrt((3-1)^2 + (1-2)^2) = sqrt 5 = 2.2361a=(31)2+(12)2=5=2.2361

Area of Delta = 12
:. h = (Area) / (a/2) = 12 / (2.2361/2) = 12 / 1.1181 = 10.7325
side b = sqrt((a/2)^2 + h^2) = sqrt((1.1181)^2 + (10.7325)^2)
b = 10.7906

Since the triangle is isosceles, third side is also = b = 10.7906

Measure of the three sides are (2.2361, 10.7906, 10.7906)