How do you simplify #(\frac { 8x ^ { 4} } { y ^ { 9} } ) ^ { 4}#?

1 Answer
Dec 11, 2017

First, remember that:
#((a^x)/(b^y))^z=(a^(xz))/(b^(yz))#
Also remember that:
#(ax)^y=a^yxxx^y#

Therefore,
#((8x^4)/(y^9))^4# is really
#(8x^4)^4/(y^9)^4# According to our second rule, this is

#(8^4xxx^16)/y^36# which is really
#(4096x^16)/y^36#