Question

Question #81d4e

Answer 1

`dy/dx[ln(ln(x))]=1/(xln(x)`

Explanation:

We apply: `(dy)/dx[ln(g(x))]=1/g(x)*(dg)/dxg(x)`

Let `g(x)=ln(x)`

So the derivative `((dg)/dx)` of `ln(x)` is `1/x`

Thus:

`(dy)/dx[ln(g(x))]=1/lnx*1/x=1/(xlnx)`