If p(x) = x^2 -1 and q(x) = 5(x-1), what is (p-q)(x)?

2 Answers
Dec 13, 2017

x^2-5x+4

Explanation:

(p-q) (x)=p(x)-q(x)=(x^2-1)-5*(x-1)=x^2-5x+4

Dec 13, 2017

x^2- 5x+4

Explanation:

Question, (p-q)(x)

Here both p and q are functions assuming (p-q)(x) means p(x)-q(x).

(p-q)(x) =
p(x)-q(x)

= p(x) - q(x)
= (x^2-1) - {5(x-1)}
= x^2-1 - {5x-5}
= x^2-1 - 5x+5
= x^2- 5x+4

Thus, (p-q)(x)=x^2- 5x+4.