Sin^2x+sin^2x cot^2x ?
2 Answers
Dec 13, 2017
Explanation:
Dec 13, 2017
See the answer below....
Explanation:
#sin^2x+sin^2x cdot cot^2x#
#=sin^2x+sin^2x cdot cos^2x/sin^2x#
#=sin^2x+cancel(sin^2x) cdot cos^2x/cancel(sin^2x) #
#=sin^2x+cos^2x#
#=1# [As identity]