Sin^2x+sin^2x cot^2x ?

2 Answers
Alok Shukla
Dec 13, 2017

#1#

Explanation:

#sin^2x+sin^2x cot^2x#

#= sin^2x*(1+cos^2x/sin^2x)#

#= sin^2x*((sin^2x+cos^2x)/sin^2x)#

#= sin^2x*(1/sin^2x)#

#= sin^2x/sin^2x#

#= 1#

Sunayan S
Dec 13, 2017

See the answer below....

Explanation:

#sin^2x+sin^2x cdot cot^2x#
#=sin^2x+sin^2x cdot cos^2x/sin^2x#
#=sin^2x+cancel(sin^2x) cdot cos^2x/cancel(sin^2x) #
#=sin^2x+cos^2x#
#=1# [As identity]

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