What is an equation of the line that passes through the points (-4, 3) and (-1, 6)?

1 Answer
Dec 14, 2017

Slope-intercept form: y=x+7y=x+7
Point-slope form: y-6=1(x+1) or y-3=1(x+4)y6=1(x+1)ory3=1(x+4)

Explanation:

To find the equation of the line, first, you must find the slope. Remember that the slope formula is

m=(y_2-y_1)/(x_2-x_1)m=y2y1x2x1

If you plug in the points (it does not matter which point is (x_1,y_1)(x1,y1),

(6-3)/(-1+4)= 1631+4=1

Therefore, the slope is 11.

Slope-intercept form:

y=mx+by=mx+b

So

3=1(-4) +b3=1(4)+b

b=7" "b=7 (bb is the same if you plug in (-1,6)(1,6))

So

y=x+7y=x+7

Point-slope form:

y-y_1=m(x-x_1)yy1=m(xx1)

You can plug in one of the two points here.

y-6=1(x+1)y6=1(x+1)

or

y-3=1(x+4)y3=1(x+4)

Hope this helped.