How do you rewrite #14x - 19y = 1# in slope-intercept form?

1 Answer
Dec 14, 2017

See a solution process below:

Explanation:

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

First, subtract #color(red)(14x)# from each side of the equation to isolate the #y# term:

#-color(red)(14x) + 14x - 19y = -color(red)(14x) + 1#

#0 - 19y = -14x + 1#

#-19y = -14x + 1#

Now, divide both sides of the equation by #color(red)(-19)# to put the equation in slope-intercept form while keeping the equation balanced:

#(-19y)/color(red)(-19) = (-14x + 1)/color(red)(-19)#

#(color(red)(cancel(color(black)(-19)))y)/cancel(color(red)(-19)) = (-14x)/color(red)(-19) + 1/color(red)(-19)#

#y = (-14)/(-19)x - 1/19#

#y = color(red)(14/19)x - color(blue)(1/19)#