Question #50761

2 Answers
Dec 14, 2017

30.072 L

Explanation:

We know that,

The atomic mass of He is 4 g=1 mol

At STP,

the molar volume of every gasses of 1mol is 22.4L

Then,at STP

The volume of 4 g He is22.4L

:.The volume of 5.37 gHe is
=(5.37 gxx22,4L)/(4 g)=30.072 L

Dec 14, 2017

See the simple steps to take in solving the question above;

Explanation:

We are dealing on two given information..

Volume and Mass..

Using this we can get the required Volume..

Recall;

n = v/(mV) = m/(mM)

Where;

n = "no of moles"

v = "volume"

m = "mass"

mV = "molar volume"

mM = "molar mass"

So we have;

v/(mV) = m/(mM)

v = ?

mV = 22.4dm^3mol^-1or Lmol^-1

N/B rArr dm^3 = L

m = 5.37g

mM = 4gmol^-1

Substitute the values into the fomula

v/(22.4dm^3mol^-1) = (5.37g)/(4gmol^-1)

v/(22.4dm^3cancel(mol^-1)) = (5.37cancelg)/(4cancelgcancel(mol^-1))

v/(22.4dm^3) = (5.37)/(4)

Cross multiplying..

v xx 4 = 22.4dm^3 xx 5.37

4v = 22.4dm^3 xx 5.37

4v = 120.288dm^3

Divide both sides by 4

(cancel4v)/cancel4 = (120.288dm^3)/4

v = (120.288dm^3)/4

v = 30.072dm^3 or 30.072L