Question #270b3

2 Answers
Jim G.
Dec 14, 2017

#v=-6" or "v=1#

Explanation:

#"rearrange and equate to zero"#

#rArr7v^2+35v-42=0larrcolor(blue)"standard form"#

#"take out a "color(blue)"common factor of 7"#

#rArr7(v^2+5v-6)=0#

#"the factors of - 6 which sum to + 5 are + 6 and - 1"#

#rArr7(v+6)(v-1)=0#

#"equate each factor to zero and solve for v"#

#v+6=0rArrv=-6#

#v-1=0rArrv=1#

#"the solutions are "v=-6" or "v=1#

Archish R.
Dec 14, 2017

#v=1 or -6#

Explanation:

#7v^2 -42 = -35v#

#7v^2+35v -42 = 0#

#7(v^2+5-6)=0#

#v^2+5-6=0#

#(v+6)(v-1)=0#

Using the 0 product property (if #ab=0#, then #a =0 or b= 0#)

#v+6=0#
#=>v=-6#

#v-1=0#
#v=1#

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