Question

Question #c0566

Answer 1

`y=-1/2x+3`

Explanation:

Using the equation of a line,
`y=mx+b`
I plugged in the known values of `m` which is my slope
and the `x`'s and `y`'s because it was given as `(-4,5)`
where `-4` was `x` and `5` was `y`

Answer 2

Point-slope form: `y-5=-1/2x+4`

Slope-intercept form: `y=-1/2x+9`

Explanation:

First determine the point-slope form of the line:

`y-y_1=m(x-x_1)`,

where:

`(x_1,y_1)` is the given point `(-4,5)` and `m` is the slope, `-1/2`.

Plug in the known values.

`y-5=-1/2(x-(-4))`

Expand.

`y-5=-1/2x+4` `larr` point-slope form

Convert the point-slope form to slope-intercept form by solving for `y`.

Slope-intercept form:

`y=mx+b`,

where:

`m` is the slope and `b` is the y-intercept.

`y-5=-1/2x+4`

Add `5` to both sides.

`y=-1/2x+4+5`

Simplify.

`y=-1/2x+9` `larr` slope-intercept form

graph{y=-1/2x+9 [-16.29, 15.74, 3.14, 19.16]}