Question #dd613

2 Answers

sinx

Explanation:

First simplify the inverse trig identities.
cscx=1/sinx; cotx=cosx/sinx
Plugging those in you get
1/sinx-cosx(cosx/sinx) multiply
1/sinx-cos^2x/sinx combine them together
(1-cos^2x)/sinx Use trig identities of squared trig functions
sin^2x+cos^2x=1 => sin^2x=1-cos^2x
sin^2x/sinx=>sinx Reduce

Dec 15, 2017

cscx-cosx*cotx=sinx

Explanation:

cscx-cosx*cotx

=1/sinx-cosx*cosx/sinx

=[1-(cosx)^2]/sinx

=(sinx)^2/sinx

=sinx