Question #4db2c

1 Answer
Swarna Islam
Dec 15, 2017

(b)#40.5@C#

Explanation:

The initial volume of argon ,V1=1 L,

The initial pressure,P1=720 mmHg

The initial temperature,T1=#20@C=(273+20)K=293K#

The decreased pressure,P2=360 mmHg

The increased volume,V2=2.4 L

The final temperature,T2=?

We know,

#(P1.V1)/(T1)=(P2V2)/(T2)#

=)T2=#(P2V2T1)/(P1V1)=313.5K=40,5@C#

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