Question #8198e

1 Answer
Dec 15, 2017

7.48 g

Explanation:

Convert volume of methane in the balloon to moles:

Density methane = 0.716 g/L at STP
3.75 x 0.716 = 2.69 g of methane

Molar Mass CH_4 = 16.04 g/mol

Using the equation: mol = mass / molar mass

Number of moles CH_4 = 2.69 / 16.04
Number of moles CH_4 = 0.17 mol

We need to write a balanced equation for this reaction to determine the molar ratio of CO_2 and CH_4

CH_4 + 2O_2 -> CO_2 + 2H_2O

CO_2 and CH_4 in 1 : 1 ratio, so 0.17 moles of CO_2 are produced in the combustion reaction.

Number of moles of CO_2 = 0.17 mol
Molar mass CO_2 = 44.01 g/mol

Rearranging the equation we used before: mass = mol x molar mass
Mass CO_2 = 44.01 x 0.17
Mass CO_2 = 7.48 g