How do you solve for D? d+7>#7d+3/3#

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Answer 1 · 2017-12-17T14:31:06

#d<1#

We can treat this like an ordinary algebra problem!

# d + 7 > 7d + 3/3 #

The first thing to note is that #3/3 = 1#

#=> d+7>7d+1 #

Subtracting #d# on both sides:

#=> 7 > 6d +1 #

Subtracting #1# on both sides:

#=> 6 > 6d #

Dividing by 6:

#=> 1 > d #

#d<1 #