What is the correct match?

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1 Answer
Dec 18, 2017

#y=A(1-r)^t# is exponential decay and #y=A(1+r)^t# is exponential growth.

Explanation:

It depends strongly on context. To make it meaningful, I assume that #y# is a function of #t# and #A,r# are some constants, where #0< r<1#.
When you exponentiate number bigger than 1 you get exponential growth and when the number is less than 1 you get decay. That's why #r>0# part is important. If #r<0# the answers would swap.

If #r=0# you get old boring constant functions.

If #r>1# then #1-r<0# and when you exponentiate negative numbers bad things would happen (if you don't know complex numbers).
Exponentiating 0 is only half-ok. You get 0 for positive t, and whole thing explodes for negative t.

Further interpretations could suggest that #t# is time and #A# is initial value of for example light intensity, electrical current, number of microbes, number of radioactive atoms, money etc.

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