Question

Question #4658d

Answer 1

`=4.83gFe_3O_4`

Explanation:

1. Find the molar mass of the involved substances
   `O_2=(32g)/(mol)`
   `Fe_3O_4=(232g)/(mol)`
2. Given the `mO_2`, convert it to `nO_2` through molar conversion with the relationship provided in the molar mass of `O_2`.
   `=2.00cancel(gO_2)xx(1molO_2)/(32cancel(gO_2))`
   `=0.0625molO_2`
3. Now, find the `nFe_3O_4`. Refer and use the balanced equation as provided for the mole ratio; i.e.,
   `=0.0625cancel(molO_2)xx(1molFe_3O_4)/(3cancel(molO_2))`
   `=0.02083molFe_3O_4`
4. Finally, find the `mFe_3O_4` through the relationship obtainable from the molar mass of the compound to convert mole to mass; thus,
   `=0.02083cancel(molFe_3O_4)xx(232gFe_3O_4)/(1cancel(molFe_3O_4))`
   `=4.83gFe_3O_4`