Question

Question #c3ce8

Answer 1

It is a function.

Explanation:

Well, first remember that `f(x)` is a function when only one `y` value can match to a specific `x` value.

Ok. Let us now solve `y` this in terms of `x`, assuming `y=f(x)`.

`x=2y^2`
`x/2=y^2`
`sqrt (x/2)=y`

We can see that there can only be one value of `y` for a specific value of `x`. Therefore, this is a function. (Limited, of course, since there can't be negative `x` values defined as a real number.