Question #848b4

1 Answer
Dec 19, 2017

epsilon = 46.7 dm^(-3)mol^(-1)cm^(-1)

Explanation:

To calculate this, we need to use the Beer-Lambert Law.
log_10(I_0/I) = A = epsilonCl
Where A = absorbance; epsilon = molar extinction coefficient (dm^(-3)mol^(-1)cm^(-1)); C = concentration (M); l = path length (cm); I_0 = incident light; I = transmitted light

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We can rearrange to solve for the molar extinction coefficient:
epsilon = A / (Cl)

The sample transmitted 20%, so we know that I = 20% Since the transmitted light is 20% of the incident light, we can take the incident light to be 100% I_0 = 100%

A = log_10(100/20)
A = 0.7

epsilon = 0.7 / (0.01 xx 1.5)

epsilon = 46.7 dm^(-3)mol^(-1)cm^(-1)