Question

What is `f(x) = int x-3e^(x)dx` if `f(0)=-2`?

Answer 1

`f(x)=x^2/2-3e^x+1`

Explanation:

`f(x)=int (x-3e^x)*dx=x^2/2-3e^x+C`

After imposing `f(0)=-2` condition, I found

`C-3=-2`, so `C=1`

Thus, `f(x)=x^2/2-3e^x+1`