How many calories are required to raise the temperature of a 11.6 g sample of iron from 22.2°C to 41.6°C?

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Answer 1 · 2017-12-20T12:58:43

24.2 calories

Using the equation:

#E = m xx C xx DeltaT#

Where #E# = energy (#J#); #C# = specific heat capacity (#Jg^(-1@)C^(-1)#); #DeltaT# = change in temperature #(.^@C)#

For iron:
#C = 0.45 Jg^(-1@)C^(-1)#

#DeltaT = 41.6 - 22.2#
#DeltaT= 19.4 ^@C#

#E = 11.6g xx 0.45Jg^(-1@)C^(-1) xx 19.4^@C #
#E = 101.3 J#

We have our answer in joules, but we need to convert this to calories.

#1 cal = 4.184 J#

#101.3 / 4.184 = 24.2 cal#