Question #da71d

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Answer 1 · 2017-12-20T14:01:09

The work done is #=3990J#

Let the acceleration due to gravity be #g=9.8ms^-2#

The potential energy of the drum at the top of the plane is

#PE=mgh=200*9.8*1.5=2940J#

The work done by the frictional force is

#W_F=F_r*d=150*7=1050J#

The total work is

#W=PE+W_F=2940+1050=3990J#