Question

How much heat must be removed to freeze a tray of ice cubes at 0C? The mass of the water is 225 g?

Answer 1

`18"kcal"`.

Explanation:

The latent heat of water freezing is `80"cal/g"` -- that amount of heat has to be removed to freeze water at a constant temperature equal to its melting/freezing point `0°"C"`.

For `225"g"` of water, the total latent heat is

`(80"cal/g")×(225"g")=18,000"cal"=18"kcal"`