Question #b58ba

2 Answers
Dec 22, 2017

A) 22g

Explanation:

Calculate this using the equation:

Mol = (Mass) / (Mr)

Mr CO = 28 g/mol
Mr CO_2 = 44 g/mol

14 / 28 = 0.5 mol

Based on the balanced equation you provided, CO and CO_2 are in a 1:1 ratio. Therefore, the number of moles of CO used = the number of moles of CO_2 produced.

Rearranging the equation for mass

Mass = Mol x Mr

0.5 xx 44 = 22g

Dec 22, 2017

The answer is option (A)=22g

Explanation:

The reaction is

2CO(g)+O_2(g)rarr 2CO_2(g)

2 moles of carbon monoxide give 2 moles of carbon dioxide

1 mole of carbon monoxide is =12+16=28g

1 mole of carbon dioxide is =12+ 2*16=44g

Therefore,

The mass of carbon dioxide is =44/28*14=22g