Question

Question #b58ba

Answer 1

A) 22g

Explanation:

Calculate this using the equation:

`Mol = (Mass) / (Mr)`

Mr `CO` = 28 g/mol
Mr `CO_2` = 44 g/mol

`14 / 28 = 0.5` mol

Based on the balanced equation you provided, `CO` and `CO_2` are in a 1:1 ratio. Therefore, the number of moles of `CO` used = the number of moles of `CO_2` produced.

Rearranging the equation for mass

`Mass = Mol x Mr`

`0.5 xx 44 = 22g`

Answer 2

The answer is option `(A)=22g`

Explanation:

The reaction is

`2CO(g)+O_2(g)rarr 2CO_2(g)`

`2` moles of carbon monoxide give `2` moles of carbon dioxide

`1` mole of carbon monoxide is `=12+16=28g`

`1` mole of carbon dioxide is `=12+ 2*16=44g`

Therefore,

The mass of carbon dioxide is `=44/28*14=22g`