What is the #"pH"# for an aqueous solution with a hydroxide concentration of #5 xx 10^(-3) "M"# at #25^@ "C"#?
2 Answers
Dec 25, 2017
Explanation:
#"pOH" = - log["OH"^-]#
Now,
#"pH" + "pOH" = 14#
Dec 26, 2017
Explanation:
Here,