Question

How do you graph `y = –2(x + 3)^2 + 1`?

Answer 1

The graph should look like this:

graph{y=-2(x+3)^2+1 [-10, 10, -5, 5]}

Explanation:

First, make a table for `x` and `y`.

Second, plug in values for `x` like `-5,-4,-3,...,0,1,2,3...`

Third, figure out the `y` values from the equation corresponding to the `x` values (in this case it's `y=-2(x+3)^2+1`)

Create an `x,y` graph and plot the points you have found.

Finally, connect the dots to receive a graph like this:

graph{y=-2(x+3)^2+1 [-10, 10, -5, 5]}