How do you complete a table for the rule #y=1.6x+1# and then graph the line?
1 Answer
Dec 26, 2017
See a solution process below:
Explanation:
For a linear equation we only need a table with two points:
Next, we can plot the two points:
graph{(x^2+(y-1)^2-0.075)((x-5)^2+(y-9)^2-0.075)=0 [-20, 20, -10, 10]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y - 1.6x - 1)(x^2+(y-1)^2-0.075)((x-5)^2+(y-9)^2-0.075)=0 [-20, 20, -10, 10]}