How do you find the limit #(x^3+4x+8)/(2x^3-2)# as #x->1^+#?
1 Answer
Dec 27, 2017
Explanation:
use direct substitution:
(
graph{(x^3+4x+8)/(2x^3-2) [0.9, 1.1, -1000, 1000]}
from the graph, you can see that the function approaches