Question

Zach traveled from city A to city B. He left city A at 7:30 a.m. and reached city B at 12 noon. Find his average speed if city B is 180 mi away from city A?

Zach traveled from city A to city B. He left city A at 7:30 a.m. and reached city B at 12 noon. Find his average speed if city B is 180 mi away from city A?

Answer 1

The elapsed time is 12:00-7:30 = 4.5 hours.

Average speed is `v_(av)=("distance")/(time)=180/4.5=40` `mph`