Question

How do you find the domain and range of `f(x)=-4+sqrt(x+3)`?

Answer 1

Suppose,`y=f(x)=-4+sqrt(x+3)`

*Here,
`f(x)=-4+sqrt(x+3)`
If we substitute the value of `x` less than`-3`,the value of equation will be indefinable. *

So,Domain`RR={x:x inRR,x>=(-3)}`

Again, for the value of domain set, the value of range set will be greater than or equal -4

So,Range`RR={y:y inRR,y>=(-4)}``color(brown)((Ans.))`