Question

How do you multiply `(-1+2i)(3+2i)` in trigonometric form?

Answer 1

`-7+4iota`

Explanation:

`iota= sqrt(-1)`
So, `iota^2=-1`

`(-1+2iota) (3+2iota)`

`-3-2iota+6iota-4`

`-7+4iota`

Simply multiply as we generally multiply polynomial by polynomial provided the rules of complex must in mind just like `iota^2=-1`.