How do you divide ( 8x^6-32x^5+4x^4 )/(x+2)? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Tamir E. Dec 30, 2017 f(x)={8x^6-32x^5+4x^4}/{x+2}={4x^4(2x^2-8x+1)}/{x+2} 2x-12 bar {2x^2-8x+1}|x+2 - 2x^2+4x = 0x^2-12x+1 - 0x^2-12x-24 = 0x^2+0x-23 => f(x)=4x^4[(2x-12)-23/{x+2}] Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide 9x^2-16 by 3x+4? How do you divide \frac{x^2+2x-5}{x}? How do you divide \frac{x^2+3x+6}{x+1}? How do you divide \frac{x^4-2x}{8x+24}? How do you divide: (4x^2-10x-24) divide by (2x+3)? How do you divide: 5a^2+6a-9 into 25a^4? How do you simplify (3m^22 + 27 mn - 12)/(3m)? How do you simplify (25-a^2) / (a^2 +a -30)? See all questions in Division of Polynomials Impact of this question 1846 views around the world You can reuse this answer Creative Commons License