What is the standard form of # y-3x= (x+2)(x-1)^2+5#?

1 Answer
Rachel
Jan 2, 2018

#y=x^3+7#

Explanation:

Standard form looks like #ax^2 + bx +c#

#y-3x = (x+2)(x-1)^2+5#

Let's expand everything

#y-3x = (x+2)(x-1)(x-1)+5#

Now we combine

#y-3x = (x^2+x-2)(x-1)+5#

#y-3x = x^3-3x+2+5#

#y-3x = x^3-3x+7#

Add #3x# to both sides

#y=x^3+7#

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