Question

How do you rewrite `y^x = 218/157` in logarithmic form?

Answer 1

`log_y(218/157) = x`

Explanation:

We can convert from exponential to logs using this idea:

`a^b=c\rightarrow log_a(c) = b`

So given `y^x=218/157` we can convert to logs:

`log_y(218/157) = x`