Question

How do you write `-8-(3+2i)-(9-4i)` in standard form?

Answer 1

`-20 + 2i`

Explanation:

Standard form for complex numbers is `a+bi`, where `a` and `b` are integers. To get this, we just have to combine all the terms with `i` and all the terms without `i`.

Simplifying the expression:

`-8-(3+2i)-(9-4i)`

`=-8-3-2i-9+4i`

Regrouping the terms:

`= (-8-3-9) + (-2i+4i)`

`= -20 + 2i`