Question #7716e

1 Answer
Jan 8, 2018

#~~3M gal#

Explanation:

The problem can be solved using the formula:
#V=Pir^2h#

Given that the #"diameter (d) is " 92ft# and the #"height(h) is " 60ft#. Knowing that #d=2r#; so that, that #r=d/2#. Therefore, #r=(92ft)/2=46ft#

Referring to the formula, plug in its values to find the volume of the water that can be stored in the cylindrical tank; i.e.,
#V=Pir^2h#
#V=3.1416xx(46ft)^2xx60ft#
#V=3.1416xx2116ft^2xx60ft#
#V=398857.536ft^3#

Or change the ft^3 to gallon; where, #1ft^3=7.48gal# to visualize the volume of water in terms of this common unit.

#V=398857.536cancel(ft^3)xx(7.48052gal)/(1cancel(ft^3))#
#V=2,983,662 gal" of water"#