Question #76346

1 Answer
Sunayan S · Paurush
Jan 9, 2018

See below....

Explanation:

1) #/_A+/_B+/_C=180^@" "……(1)#
2) #/_B-/_A=^@45 " "…… (2)#
3) #/_B-/_C=15^@" " …… (3)#

  • On adding #(2)# and #(3)#
    #2/_B-/_A-/_C=60^@" "…(4)#

  • On adding #(1)# and #(4)#
    #3/_B-/_A-/_C+/_A+/_C=240^@#
    Therefore, #3/_B=240^@#
    #=>B=80^@#

  • Putting #/_B# in #(2)#
    #/_A=35^@#
    Putting #/_B# in #(3)#
    #/_C=65^@#

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