Question #be455
1 Answer
Jan 9, 2018
Explanation:
#"here are two possible approaches "#
#color(blue)"Approach 1"#
#"add the fractions on the left "#
#"the "color(blue)"lowest common multiple of 3 and 2 is 6"#
#rArr5/3xx2/2p=10/6p" and "3/2xx3/3p=9/6p#
#rArr10/6p+9/6p=19/10#
#rArr(19p)/6=19/10#
#"multiply all terms by 30"#
#cancel(30)^5xx(19p)/cancel(6)^1=cancel(30)^3xx19/cancel(10)^1#
#rArr95p=57#
#"divide both sides by 95"#
#rArrp=57/95=3/5#
#color(blue)"Approach 2"#
#"multiply all terms by the lowest common multiple"#
#"the lowest common multiple of 3, 2 and 10 is 30"#
#rArr50p+45p=57#
#rArr95p=57#
#rArrp=57/95=3/5#
