Question

Question #2b63f

Answer 1

See below.

Explanation:

Let's say we have a rhombus like one below.

First of all, if we know the length of one side, then we know the length of all the others. We name the length `s`.

Second, we have our diagonal `d`.

We could view this as two separate triangles separated by the diagonal.
Esentially, we could add the areas of these two triangles.

We use Heron's formula: `A=sqrt(s*(s-a)*(s-b)*(s-c))`
where `a,b,c` are the length of the sides of the triangle and `s` is the semi perimeter.

We see that both of the triangles have the side lengths of `s,s,d`

Using heron's formula, we have:
`A=2(sqrt(((2s+d)/2)*((2s+d)/2-s)*((2s+d)/2-s)*((2s+d)/2-d)))`

We are multiplying by 2 because both of the two triangles have the same side lengths.
You could plug the values in this to find your answer.