Question #90a80

1 Answer
Jan 10, 2018

No solutions.

Explanation:

#6y - 9 <= 4y + 2y - 16#

#6y - 9 <= 6y - 16#

#6y <= 6y - 7#

To more easily think about this logically, let's substitute #6y# for #n#.

#n <= n - 7#

Now, is it ever possible for a number to be less than or equal to 7 less than itself? This is simply impossible, so there is no solution.

Algebraically, we can see why there is no solution by continuing to solve as normal.

#6y <= 6y - 7#

#0 <= -7#

As we know, #0# is never less than or equal to #-7#, so there are no values for #y# for which #6y - 9 <= 4y + 2y - 16#.