What will be the escape velocity from a planet whose mass is 6 times that of the earth and radius is twice that of the earth considering v is the eascape velocity from earth?

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Answer 1 · 2018-01-11T11:26:16

The escape velocity is #=(sqrt3v)ms^-1#

The escape from the earth is

#v=sqrt((2GM)/r)#

#G# is the gravitational constant

#M# is the mass of the earth

#r=# is the distance from the center of mass of the body to the object

On the planet

#M_1=6M#

#r_1=2r#

Therefore,

#v_p=sqrt((2GM_1)/r_1)=sqrt((2G*6M)/(2r))#

#=sqrt(((2GM)/r)*3)#

#=sqrt3v#