Question

A projectile is shot from the ground at a velocity of `2 m/s` and at an angle of `(7pi)/12`. How long will it take for the projectile to land?

Answer 1

0.4 sec

Explanation:

Throwing a projectile at an angle `7(pi/12)` means it has been thrown at an angle of `5(pi/12)` w.r.t to the horizontal on to the opposite direction.
Hence,time taken by the projectile to ascend upto its highest point can be calculated using `v=u+at` (all symbols are bearing their conventional meaning)
Here,`v=0` , u=`2 sin 5(pi/12)` ,`a=-g`
So,t=0.2 sec
It will take the same amount of time to get down.
Hence total time to land will be `(2*0.2)` sec or 0.4 sec