What is the concentration of a $20.0573 \cdot g$ $20.0573g$ mass of potassium hydroxide dissolved in an aqueous solution of $399 \cdot m L$ $399mL$ volume?

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What is the concentration of a $20.0573 \cdot g$ $20.0573g$ mass of potassium hydroxide dissolved in an aqueous solution of $399 \cdot m L$ $399mL$ volume?

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Answer 1 · 2018-01-11T21:12:44

$[K O H] ≅ 0.9 \cdot m o l \cdot L^{- 1}$ $[KOH]~=0.9*mol*L^-1$

Explanation:

By definition....

$Molarity = \frac{Moles of solute (mol)}{Volume of solution (L)}$ $"Molarity"="Moles of solute (mol)"/"Volume of solution (L)"$

And so here we just fill in the details....

$\frac{\frac{20.0537 \cdot g}{56.1080 \cdot g \cdot m o l^{- 1}}}{399 \cdot m L \times 10^{- 3} \cdot L \cdot m L^{- 1}} = ? ? \cdot m o l \cdot L^{- 1}$ $((20.0537*g)/(56.1080*g*mol^-1))/(399*mLxx10^-3*L*mL^-1)=??*mol*L^-1$

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What is the concentration of a $20.0573 \cdot g$ $20.0573g$ mass of potassium hydroxide dissolved in an aqueous solution of $399 \cdot m L$ $399mL$ volume?

1 Answer

Explanation:

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What is the concentration of a 20.0573⋅g20.0573*g mass of potassium hydroxide dissolved in an aqueous solution of 399⋅mL399*mL volume?

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What is the concentration of a $20.0573 \cdot g$ $20.0573g$ mass of potassium hydroxide dissolved in an aqueous solution of $399 \cdot m L$ $399mL$ volume?