Question #2f1a4

1 Answer
Jan 12, 2018

About 1%

Explanation:

For smaller change in amount of length we can say,
{(del T)/T}= (1/2)*{((del L)/L)+((del g)/g)}
As the change in g is zero,hence we can say change in time period= {(1/2)*2} or 1%

Alternatively,
Let us assume that initial time period,
T=(2pi)√(l/g)
Final Tf=(2pi)
√(1.02l/g)
I.e equals to 1.0099*T
So,change in Time period is 0.0099 or 0.99 % ~_ 1%