Question #2f1a4

1 Answer
Jane
Jan 12, 2018

About 1%

Explanation:

For smaller change in amount of length we can say,
#{(del T)/T}#= #(1/2)*{((del L)/L)+((del g)/g)}#
As the change in g is zero,hence we can say change in time period= #{(1/2)*2}# or 1%

Alternatively,
Let us assume that initial time period,
T=#(2pi)##√(l/g)#
Final Tf=#(2pi)##√(1.02l/g)#
I.e equals to #1.0099*T#
So,change in Time period is 0.0099 or 0.99 % #~_# 1%

Related questions
Impact of this question
687 views around the world
You can reuse this answer
Creative Commons License