Question

Question #2f1a4

Answer 1

About 1%

Explanation:

For smaller change in amount of length we can say,
`{(del T)/T}`= `(1/2)*{((del L)/L)+((del g)/g)}`
As the change in g is zero,hence we can say change in time period= `{(1/2)*2}` or 1%

Alternatively,
Let us assume that initial time period,
T=`(2pi)``√(l/g)`
Final Tf=`(2pi)``√(1.02l/g)`
I.e equals to `1.0099*T`
So,change in Time period is 0.0099 or 0.99 % `~_` 1%