Question

Question #b6f49

Answer 1

`color(blue)(164gAl_2O_3)`

Explanation:

First, write a balanced equation:
`4Al(s) + 3O_2(g) -> 2Al_2O_3`

Then, use the equation to determine how many moles of `Al_2O_3` will be created when 3.23 moles of aluminum reacts:
`3.23molAl*((2molAl_2O_3)/(4molAl)) = 1.615molAl_2O_3`

Finally, convert into grams:
`1.615molAl_2O_3*((102gAl_2O_3)/(1molAl_2O_3)) = 164.73 ~~ 164gAl_2O_3`