How to solve properly int tan(x)/cos^2x?
I have a doubt on how to solve this integral.
The first and the correct way to solve is:
int (tan x) /cos^2x dx
Let's rewrite
int sin x / cos^3x dx
With the u substitution:
u = cos x , so du = -sin x
-int1/u^3du = 1/(2u^2) + C
Substitute the original value and the result is:
1/(2cos^2x)+C
The second way with the mistake is:
int (tan x) /cos^2x dx
int (tan x) * 1/cos^2x dx
u = tan(x) , so du = 1/cos^2x
Which means:
int u \ du = u^2/2+C
tan^2x/2 + C
I have a doubt on how to solve this integral.
The first and the correct way to solve is:
Let's rewrite
With the
Substitute the original value and the result is:
The second way with the mistake is:
Which means:
1 Answer
Jan 13, 2018
The answer is
Explanation:
Reminder :
Apply
Therefore,
Perform the substitution
Therefore,