A 4.00 ✕ 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.600 m by a large spring bumper at the end of its track. What is the force constant k of the spring (in N/m)?
3 Answers
291.67
Explanation:
Here in this case,the kinetic energy of the bus got stored as elastic potential energy of the spring as a result of stopping it.
So,if the spring gets compressed by a distance of
its elastic potential energy stored will be
And if the bus of mass
So,equating both, we get,
The spring constant is
Explanation:
The mass of the train is
The speed of the train is
The kinetic energy of the train is
The energy stored in the spring is
The spring constant is
The compression of the spring is
As,
Explanation:
Firstly we can calculate the deceleration of the train:
We can use Newton's Law to find the force needed to stop the train:
This force will be provided by the buffer for which we use Hooke's Law: