A container with a volume of #18 L# contains a gas with a temperature of #170^o C#. If the temperature of the gas changes to #640 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-01-14T06:37:04

The new volume is #=26L#

Apply Charles' Law

#"volume"/"Temperature"="Constant"#, #"At constant pressure"#

#V_1/T_1=V_2/T_2#

The initial volume is #=V_1=18L#

The initial temperature is #T_1=170+273=443K#

The final temperature is #T_2=640K#

The final volume is

#V_2=T_2/T_1*v_1=640/443*18=26L#