Question

Question #c05da

Answer 1

`y = -x+ 6` which is in the form `y = mx + c`

Explanation:

Slope of line L1 is `m_L = tan (45) = 1`

Slope of the line L1 perpendicular to L `= -1/(m_L) = -1`

Equation of L1 with slope -1 and passing through point (6,0) is

`y - y1 = m (x - x1)`

`y - 0 = -1 * (x - 6)`

`y = -x + 6` which is in the form `y = mx + c`