Question #97e1b

1 Answer
Jan 15, 2018

#x=pi*n# where #n in ZZ#.

Explanation:

The Pythagorean Identity says: #cos^2(x)+sin^2(x)=1# which means we can rewrite the original:

#2sin^2(x)=1-1 rarr 2sin^2(x)=0 rarr sin(x)=0#

If #sin(x)=0# we know #x=0+2pi*n# where #n in ZZ# or #x= pi + 2pi*n# where #n in ZZ#.

We could also simplify this to #x=pi*n# where #n in ZZ#.